LESSON PLAN MOLECULAR SHAPE


LESSON PLAN
I. Identity
School : SMA NEGERI 1 BATANGHARI
Subject : Chemistry
Year/semester : XII MIA 3/1
Time Allotment : 3 hours (3 x 45minutes)

II. Standard Competence
Understanding atomic structure to predict periodicity of elements, molecular structure, and properties of compounds.

III. Basic Competence
1.            Explain theory of electronic pair around atomic nucleus and theory of hybridization to predict molecular shapes

IV. Indicators
1.2.1        Predict the shapes of molecules according to pair electron theory
1.2.2        Predict the shapes of molecules according to hybridization theory

V. Learning Outcomes
1.      Student be able to predict molecular shape by using VSEPR theory
2.      Student be able to predict molecular shape by using hybridization theory

VI. Teaching and Learning Topics
  1. Domain Electron Theory and VSEPR Theory
  2. Molecular shapes
  3. Hibridization Theory
Contents
The shape of a molecule deal with the position of atoms in the molecule. In this case shapes of molecules describe the position of atoms in the three dimensional space and the magnitude of the bond angle which occurs at the covalent bond in a molecule.

1. Electron Domain Theory
Electron domain theory is one away on predict the molecular shape according to repulsion of electron in out-shell centre atom. Electron domain is electron position or occupied electron area. The number electron domain is determined such as:
Each bonded atom is counted as one region of high electron density, whether the bonding is single, double, or triple.
Each unshared pair of valence electrons on the central atom is counted as one region of high electron density.

2. VSEPR (Valence Shell Electron Pair Repulsion) Theory
VSEPR (Valence Shell Electron Pair Repulsion) Theory is a concept used to predict geometric shape formed by atoms in molecules which are covalently bonded. This theory is based on the idea that all electron pairs which are directly attached to an atom, those are bonded electron pairs and non-bonded electron pairs (free electron pairs) at around the central atom, will arrange their position to be as far away from each other as possible. Bonded electron pairs are valence electron share by atoms in a molecule, while non-bonded electron pairs or free electron pairs are valence electrons in which a molecule at locations where those electrons are not involved in the bonding process.
According to VSEPR theory, non-bonded electron pairs or free electron pairs have a greater repulsion than bonded electron pairs, so these non-bonded electron pairs occupy the larger space than bonded electron pairs. They will adopt a shape so repulsions between those electron pair will be evenly distributed and at a minimum. As a result of these repulsions, atoms will form the certain geometries; those are linear, trigonal planar, tetrahedral, trigonal bipyramidal, and octahedral shapes.
The basic ideas of the valence shell electron pair repulsion (VSEPR) theory are:
Each set of valence shell electrons on a central atom is significant. The sets of valence shell electrons on the central atom repel one another. They are arranged about the central atom so that repulsions among them are as small as possible.

3. Predicting Shape of Molecule Using VSEPR Theory
The five basic molecular shapes.
a. Linier. A linier arrangement of atoms occurs when they are all in a straight line. The angel formed between two bonds that go to the same central atom, which we call the bond angle is 180o.

b. Planar triangular. A planar triangular arrangement of four atoms has them all in the same plane. The central atom is surrounded by three others located at the corners of a triangle. The bond angels are all 120o.

c. Tetrahedral. A tetrahedron is a four-sided pyramid having equilateral triangles as faces. In a tetrahedral molecule, the central atom is located in the center of this tetrahedron and four other atoms are located at the corners. The bond angels are all equal and have values of 109.5o.

d. Trigonal bipyramid. A trigonal bipyramid consist of two triangular pyramids (similar to tetrahedrons) that share a common face. In a trigonal bipyramid molecule, a central atom is surrounded by five other. The central atom is located at the five corners. In this kind of molecule, the bond angels are not the same. Between any two bonds that lie in the central triangular plane, the bond angel is 120o. The angle is only 90o between a bond in the central triangular plane and a bond that points to the top or bottom of the trigonal bipyramid.

e. Octahedral. An octahedron is a geometrical figure that has eight faces. We can think of it as two square pyramids that share a common square base. Notice that octahedron has only six corners even thought it has eight faces. In an octahedral molecule, the central atom is surrounded by six others. The central atom is located in the center of the square plane that passes through the middle of the octahedron. The six atom bonded to it are at the six corners of the octahedron. The angel between any pair of adjacent bonds is the same, and has a value of 90o.
Molecular shape will as same as whit the electron geometric in central atom if there were not non-bonding electron. The steps to predict molecular shape such as:
  1. Write down the electron configuration each atom in molecule
  2. Determine the valence electron all atoms in molecule
  3. Draw electron-dot structure (Lewis structure)
  4. Determine bonded electron pairs and lone pairs electron of central atom
  5. Determine molecular shape
The formula of electron pairs in a molecule is symbolized as follows.
AXnEm
Information           A = central atom
X = bonded electron pairs
E = lone pairs electron
n = the number of  bonded electron pairs
m = the number of  lone pairs electron
Example : H2O molecule
Electron configuration of  8O = 1s2 2s2 2p4 (valence electron 6)
Electron configuration of  1H = 1s1 (valence electron 1)
One atom O are bonded with 2 atoms H  with lewis structure such as =
Bonded electron pairs: 2
Lone pairs electron: 2
Formula of electron pairs: AX2E2
Molecular shapes : bent (V)

1. Hybridization of Atomic Orbital Theory
According to Pauling orbital of valence electrons can form a new set orbital called hybrid atomic orbital or hybrid orbital. The process of hybrid orbital formation done by an atom is called hybridization. These hybrid orbital influences the shape of a molecule formed when the atom combines with other atoms.
a.       The sp Hybrid Orbital
The sp orbital are possible states of electrons in atom when the atom is bonded to others and these electrons states have half 2s orbital and half 2p orbital characters. Mathematically, there are two ways to combine the 2s and 2p atomic orbital.

b.      The sp2 Hybrid Orbital
Energy states of valence electrons in atoms of the second period are in the 2s and 2p orbital. If we combine two of the 2p orbital with a 2s orbital, we will obtain three sp2 hybridized orbital.

c.       The sp3 Hybrid Orbital
If we combine three of the 2p orbital with a 2s orbital, we will obtain four sp3 hybridized orbital. For example, CH4 molecule which is tetrahedral in shape can be explained by using the sp3 hybrid orbital concept.

d.      The d2sp3 Hybrid Orbital
If two 3d orbital; one 3s orbital; and three 3p orbital are combined, six d2sp3 hybrid orbital are resulted. For example, SF6 is a molecule which is d2sp3 hybridized. If an atom makes use the d2sp3 hybrid orbital to bond six other atoms, geometry of the molecule is octahedral.

e.       Hybridization with Free Electron Pairs
Among of sp2; sp3; dsp3; and d2sp3 hybridized orbital, one of the orbital may be occupied by pair or a single electron. It can influence the shape of the molecule. For example, the C, N, and o atoms in CH4, NH3, and H2O molecules use the sp3 hybrid orbital. CH4 molecule has no free electron pair, so it is tetrahedral in shape. Meanwhile, NH3 has a free electron pair and H2O has two free electron pairs, so NH3 is trigonal  pyramidal in shape and H2O is bent.

VII. Teaching-Learning Method
1.      Class discussion (use visualization)
2.      Ask and Question

VIII. Teaching and Learning Process
1.      Preparation (± 10 minute)
a)      Greetings and Introductions
b)      Checking students attendance
c)      Presenting the learning outcomes and the assessment procedure
d)     Apperception and motivation (focusing) about lewis structure
2.      Mains Activities (± 120 minutes)

Teacher Activities

Student Activity Time Allocation Location
Exploration Class room
Motivate the student with some questions related to the topics that will learn. Students answer the teacher question.  15 minutes
Elaboration
–    Presenting the topics, collecting information and problem that have students  –    Guiding the students to investigate understanding the shape of molecule according to VSEPR theory and hybridization theory
–    Observing the student’s activity
Paying a good attention to the teacher’s explanation, Give information answer the teacher’s question 60 minutes
Confirmation
–    Giving some exercises  –    Giving a comment about the asks and giving a explanation if there is misconception
–    Post test
–      Doing exercises given by teacher  –      Correcting the ask according to the teacher’s comment 45 minutes

3.      End Activities (± 5 minutes)
a.       Making the conclusion about the topic together (the students and the teacher)
b.      Giving homework
c.       Giving information of the next topic
d.      Greetings

IX. TEACHING AND LEARNING RESOURCES
1.      Chemistry book :
a.       Brady, James E and Gerard E Humiston. 1982.General Chemistry Principles and Structure. New York: John Wiley and Sons.
b.      Chang, Raymond. 2005. Kimia Dasar Konsep Konsep Inti Jilid II. Jakarta: Erlangga.
c.       Parning, Horale, Tiopan. 2008. Kimia SMA XI Semester Pertama. Jakarta: Yudistira.
d.      Sunardi. 2008. Kimia Bilingual Kelas XI SMA. Bandung: Yrama Widya.
2.      Student worksheet (Exercise)
3.      Power Point

X. MATERIAL
a. Student Worksheet
b.Laptop
c. LCD

XI. ASSESSMENT
1. Evaluation Method:    Test, individual assignment, small test.
2. Type of evaluation: Essay and multiple choice test
3. Instrument: cognitive and affective assessment rubric

Komentar

  1. Why does the CH4 molecule have no free electron pairs, so is the tetrahedral shape explained?

    BalasHapus
    Balasan
    1. Because Atoms in a tetrahedron-shaped molecule will be in a triangular pyramid space with all four areas of equilateral triangular surface. The central atom lies at the center of the tetrahedron and the other four atoms will be at the four vertices having a bond angle of 109.5 °. The example of a tetrahedron molecule is CH4.

      Hapus

  2. What is the best media learning for this lesson so the students can be understand about the moleculer shapes?
    @hudiaumamifaisal

    BalasHapus
    Balasan
    1. Can use a projector that shows an interesting drawing of the molecule as it describes it, as well as the molecular form props themselves.

      Hapus
  3. in there any rpp socialization before making rpp, so that rpp is effective and efficient when created

    BalasHapus
    Balasan
    1. Before making the rpp of course must be carefully thought out the concept so as not to make it difficult for the teacher to explain it and the students who listen to it, in making the rpp there is no need for socialization, because this is only the task of a teacher, so rpp made with simple easy to understand and cover all material be delivered.

      Hapus
  4. why do you need a laptop in your material?please explain

    BalasHapus
    Balasan
    1. I use the laptop on my rpp because it will make it easier for me to explain the shape of the molecule, and siswapun be more understanding and understand the material. Of course the laptop that I connect to the projector so that all students can see it, with the laptop also my material will be more interesting for student students, so they do not quickly get bored and quickly understand in my material.

      Hapus
  5. How the method you use to get students to understand the atomic structure?

    BalasHapus
    Balasan
    1. Can be with some methods:
      1. Learning Methods Recitation is a method of teaching by requiring students to make resumes with their own sentences.

      2. The experimental learning method is a way of managing learning in which students perform experimental activities by experiencing and proving themselves something they learn. In this method students are given the opportunity to experience themselves or to conduct themselves by following a process, observing an object, analyzing, proving and drawing its own conclusions about the object being studied.

      3. Demonstration as a learning method is when a teacher or a demonstrator (outsider is deliberately requested) or a student shows to the whole class or process.

      4. Discussion learning method is the process of involving two or more participants to interact with each other, and or mutual opinion in solving the problem so as to obtain agreement among them.

      Hapus
  6. Classroom learning seeks to follow the path: introduction, core activity, cover (end of learning). Why should it be so? What if not so?

    BalasHapus
    Balasan
    1. If it does not mean we can not arrange the rpp correctly, and it could be that the classroom is chaotic and difficult to control. And also our learning material becomes unplanned and neatly arranged, so we could be confused because we do not have a good rpp and correct.

      Hapus
  7. what'S important Giving homework?

    BalasHapus
    Balasan
    1. Homework is very important given to the students, because it is one way for students to repeat the lesson at home, and the students also become familiar with the task given so that when the big becomes less lazy when given the task, and homework helps train students to full responsible.

      Hapus
  8. What is relenthsioship between motivatin, eleboration, and confirmation?

    BalasHapus
    Balasan
    1. Motivation is useful to reframe belief system and mindset so that it can eliminate the mental block which causes the inhibition of success that should he feel. Thus allowing individuals to change themselves to be always positive, and can achieve the maximum target.
      Motivation in a person must be maintained its existence. Because sometimes the motivation in a person can be reduced or even lost due to many external and internal factors. But the most important is the internal factor of himself called Self Image located within the Sub-conscious.
      If the self-concept that he has tends to be negative, it can cause you to be easily desperate, narrow-minded, pessimistic, resisting new things. But if the self-concept that he has is positive, then believe me .. will be so eager to face life, optimistic, ready to face all challenges, full of creation and innovation
      Therefore motivation is very important for a person, because it is our "extra energy source". Which we can use at times when we experience severe problems or encounter "stumbling blocks" on our way to success.
      Motivation is likened to fuel to spur our spirit in reaching goal, and success we have dreamed of before.

      Hapus

Posting Komentar

Postingan populer dari blog ini

CAUSE AND EFFECTS

ESTER

STOICHIOMETRY